1.2. Subspaces#
Let \(U\) be a subset of the vector space \(V\). We say that \(U\) is a vector subspace of \(V\)(or simply subspace of \(V\)) if \(U\) is also a vector space with the same addition and scalar multiplication defined on \(V\).
To check whether a given subset \(U \subseteq V\), we may simply check that if \(U\) contains the zero vector and if it is closed under the addition and scalar multiplication.
Let \(U\) be a subset of \(V\). Then \(U\) is a vector subspace of \(V\) if and only if
\(\mathbf{0} \in U\),
\(\mathbf{u} + \mathbf{v} \in U\) for all \(\mathbf{u}, \mathbf{v} \in U\), and
\(a \mathbf{u} \in U\) for all \(a \in \F\) and \(\mathbf{u} \in U\).
By simple observations, one may notice that the additive identity in the subspace \(U\) is exactly the one in the superspace \(V\) and \(\mathbf{w}\) is the additive inverse of \(\mathbf{u}\) in \(U\) if and only if it is also the additive inverse of \(u\) in \(V\).
\(\{\mathbf{0}\}\) and \(V\) are subspaces of \(V\), which are the simplest examples of vector spaces.
\(\{(x, 0, 0) \mid x \in \F\}\) and \(\{(x, y, 0) \mid x, y \in \F\}\) are subspaces of \(\F^3\). Specially, when \(\F = \R\), this means that the 1D \(x\)-axis line and the 2D \(x\)-\(y\) plane are subspaces of the 3D space.
In fact, all 1D lines and 2D planes that pass through the origin are subspaces of the 3D space.